Topic 6: Organic Chemistry

1. Why is 2-Bromopropane the major product of the reaction of propene and HBr?

Because the intermediary carbocation is more stable (the charge is spread over more atoms)
It is not, the products are equally likely as propene is symmetrical
There is less steric hinderance for the reaction compared to 1-Bromopropane
The H will attack where there are fewer H's already

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....made of p-orbitals that overlap sideways to form a sigma bond, split in electron density above and below the nuclei plane
... more than twice as strong as the C-C bond due to the electron-dense sigma bond
... not quite twice as strong as the C-C bond, due to the presence of the pi bond
...made of 2 pi bonds, overlapping end-on

A ketone can be formed from the oxidation by distillation of a primary alchol
A ketone has an C=O group in the middle of it's molcule, thus with an alkyl group on each side. In an aldehyde the C=O is found at the end of the molecule with an H and an alkyl group
An aldehyde has an C=O group in the middle of it's molcule, thus with an alkyl group on each side. In a ketone the C=O is found at the end of the molecule with an H and an alkyl group
An ketone will form a dark red precipitate of Copper(I) Oxide with Fehling's solution but an aldehyde will not

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