**Solutions**

A) divide size of smallest eukaryotic cell by size of prokaryotic cell:

(1 x 10^-5) / (1.2 x 10^-6) = approximately 10 (10^1)

Therefore prokaryotic cell is one order of magnitude smaller than the smallest eukaryotic cells

B) divide size of largest eukaryotic cell by size of prokaryotic cell:

(1 x 10^-4) / (1.2 x 10^-6) = approximately 100 (10^2)

Therefore prokaryotic cell is two orders of magnitude smaller than the largest eukaryotic cell

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