PROOF OF ARTHIMETIC PROGRESSION
Sn = a+(a+d)+(a+2d)......+[a+(n-2)d]+[a+(n-1)d]
Sn =[a+(n-1)d]+[a+(n-2)d]+...+(a+2d)+(a+d)+a
2Sn=[2a+(n-1)d) + [2a+(n-1)d].........
2Sn= n[2a+(n-1)d]
Sn =n/2[2a+(n-1)d] or n/2[a+L] Nth term= [a+(n-1)d]
make sure you double check the years as these can be confusing
a = 1st term in sequence d= is the difference of sequence
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